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Question A 2268 No worries! We‘ve got your back. Try BYJU‘S free classes today! B 2520 Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses C 2975 No worries! We‘ve got your back. Try BYJU‘S free classes today! D 1560 No worries! We‘ve got your back. Try BYJU‘S free classes today!
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Solution The correct option is B 2520 The conditions are: 1. The digits from 1 to 5 should be in their natural order. 2. The digit 6 should be placed such that the digits 1 to 6 DO NOT occur in their natural order. 3. The other digits: 7, 8 and 9 are placed in other places. We only have one way of doing step 1. We have 5 digits and 6 spaces like this: _1_2_3_4_5_ In doing step 2, we can place the digit 6 in any of the first 5 spaces. Thus we have 5 ways of doing step 2. Similarly, in doing step 3, we have 7, 8 and 9 ways of placing the digits 7, 8 and 9 respectively. So, there are 1×5×7×8×9=2520 numbers that satisfy the given conditions.
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